Question

Jeffrey Lebowski rolls his bowling ball down the lane with the thumb hole perfectly lined up...

Jeffrey Lebowski rolls his bowling ball down the lane with the thumb hole perfectly lined up to rotate perpenducilar to the horizontal. (What a dude!) The ball is rolling without slipping at 7.00 m/s. The diameter of a bowling ball is 12.7 cm. Think of the circular motion of the thumb hole as vertical simple harmonic motion.

What is the frequency of the the thumb hole being at the top of the ball?

Hz

What is the apparent vertical speed of the thumb hole when it is at the top of the ball?

m/s

What is the appraent vertical speed of the thumb hole when it is halfway between the top and bottom of the ball?

m/s

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Homework Answers

Answer #1

Given,

Diameter of the Ball = 12.7 cm

Radius = 6.35 cm

Perimeter = 2*Pi*r = 39.8 cm = 0.398 m

Speed of the ball = 7 m/s

(a) NO. of revolution is 1 second = 7/0.398 = 17.58 .

So, Frequency of the the thumb hole being at the top of the ball = 17.58

(b) At the top the vertical component of the motion of the hole would be Zero and it would be moving tangentially to the direction of motion.

so, Vverticle (hole at top) = 0 (Ans)

(c) we know that,

so, 7/0.0635 = 110.2 radiun/ sec

V(hole at halfway) = = 9.89 m/sec (Ans)

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