Question

A circular brass plug needs to pass through a square hole in an iron sheet. At...

A circular brass plug needs to pass through a square hole in an iron sheet. At room temperature (20◦C), the diameter of the plug is 8.755 cm and the length of each side of the square is 8.740 cm. At what temperature must the iron sheet be brought in order for the brass plug to fit through the square hole? The brass plug is not heated. The coefficient of linear expansion for iron is 12 × 10−6/◦C. (The answer is 163 C)

Homework Answers

Answer #1

Thanks you.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A brass plug is to be placed in a ring made of iron. At 16 ?C,...
A brass plug is to be placed in a ring made of iron. At 16 ?C, the diameter of the plug is 8.793 cm and that of the inside of the ring is 8.778 cm . They must both be brought to what common temperature in order to fit? What if the plug were iron and the ring brass?
A brass plug is to be placed in a ring made of iron. At 20 ∘C,...
A brass plug is to be placed in a ring made of iron. At 20 ∘C, the diameter of the plug is 8.735 cm and that of the inside of the ring is 8.722 cm . A) They must both be brought to what common temperature in order to fit? B) What if the plug were iron and the ring brass?
A brass plug is to be placed in a ring made of iron. At 10 ∘C,...
A brass plug is to be placed in a ring made of iron. At 10 ∘C, the diameter of the plug is 8.741 cm and that of the inside of the ring is 8.729 cm . 1.They must both be brought to what common temperature in order to fit? 2.What if the plug were iron and the ring brass?
A brass plug is to be placed in a ring made of iron. At 20°C, the...
A brass plug is to be placed in a ring made of iron. At 20°C, the diameter of the plug is 8.740 cm and that of the inside of the ring is 8.730 cm. (a) They must both be brought to what common temperature in order to fit? (b) Repeat part (a) if the plug were iron and the ring brass.
A brass plug is to be placed in a ring made of iron. At 15∘C, the...
A brass plug is to be placed in a ring made of iron. At 15∘C, the diameter of the plug is 8.900 cm and that of the inside of the ring is 8.889 cm . They must both be brought to what common temperature in order to fit?
A brass plug is to be placed in a ring made of iron. At 15∘C, the...
A brass plug is to be placed in a ring made of iron. At 15∘C, the diameter of the plug is 8.864 cm and that of the inside of the ring is 8.855 cm . They must both be brought to what common temperature in order to fit?
A brass ring with inner diameter 2.00 cm and outer diameter 3.00 cm needs to fit...
A brass ring with inner diameter 2.00 cm and outer diameter 3.00 cm needs to fit over a 2.00-cm-diameter steel rod, but at 20 degrees Celsius the hole through the brass ring is 40 μm too small in diameter. To what temperature, in degrees Celsius, must the rod and ring be heated so that the ring just barely slips over the rod?
At 20∘C, the hole in an aluminum ring is 2.100 cm in diameter. You need to...
At 20∘C, the hole in an aluminum ring is 2.100 cm in diameter. You need to slip this ring over a steel shaft that has a room-temperature diameter of 2.107 cm To what common temperature should the ring and the shaft be heated so that the ring will just fit onto the shaft? Coefficients of linear thermal expansion of steel and aluminum are 12×10−6 K−1 and 23×10−6 K−1 respectively.
At 20∘C, the hole in an aluminum ring is 2.200 cm in diameter. You need to...
At 20∘C, the hole in an aluminum ring is 2.200 cm in diameter. You need to slip this ring over a steel shaft that has a room-temperature diameter of 2.204 cm . To what common temperature should the ring and the shaft be heated so that the ring will just fit onto the shaft? Coefficients of linear thermal expansion of steel and aluminum are 12×10-6K-1 and 23×10-6K-1 respectively. Express your answer in degrees Celsius to two significant figures.
2 parts thx! 1. A flat aluminum plate has a circular hole of diameter 1.739 cm...
2 parts thx! 1. A flat aluminum plate has a circular hole of diameter 1.739 cm at 0.00 °C.What is the change in its diameter when the temperature of the plate is increased to 116 °C? For reference, the coefficient of thermal expansion for aluminum is 2.3 x 10-5/C°. Give at least 2 significant figures in your answer, which should be in cm. 2. A flat plate made of an unknown metal has a circular hole of diameter 2.89 cm...