Question

Estimate the acceleration due to gravity at the surface of Europa (one of the moons of...

Estimate the acceleration due to gravity at the surface of Europa (one of the moons of Jupiter) given that its mass is 4.9

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Since

1. F=ma ( or W=mg) and

2. F=GmM/R2

3. ?Earth=?Europa

we have

WEarth = mgEarth
GmM/R2 =mgEarth
   GMErart/REart2 = gEarth similarly

WEuropa = mgEuropa

GMEuropat/REuropa2 = gEaropa

But

MEarth/ MEuropa= 5.97x1024 /4.9x1022 =122

VEarth =(4/3)?REarth3

VEuropa =(4/3)?REuropa3

VEarth /VEuropa= (REarth / REuropa)3= MEarth/MEuropa= 122

REarth / REuropa= 5 thatis

REarth = 5 R Europa

then

gEarth / gEuropa = [GMEarth/REarth2 ]/ [GMEuropa/REuropa2 ]

gEarth / gEuropa = [ MEarth    /MEuropa][REuropa/REarth]2  

gEarth / gEuropa =[  122 ][1/5]2   = 4.88

gEuropa =gEarth /  4.88

gEuropa = 9.8/4.88=2.0m/s2

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
acceleration due to gravity at earths surface is 9.80m/s2 .what is the acceleration due to gravity...
acceleration due to gravity at earths surface is 9.80m/s2 .what is the acceleration due to gravity at a distance 5 times the radius of the earth from the center of the earth
Consider the four Galilean moons of Jupiter: Io, Europa, Ganymede, and Callisto. Use the data below...
Consider the four Galilean moons of Jupiter: Io, Europa, Ganymede, and Callisto. Use the data below to find the average magnitude of the gravitational force that the Jupiter exerts on each of those moons. Use scientific notation and round the coefficient to two decimals. See info for this homework if you're not sure about the format. Jupiter's mass: 1.9×1027 kg Moon: Mass (kg) Average orbital distance from Jupiter (m) Io 8.93×10 22 4.22×10 8 Europa 4.80×10 22 6.71×10 8 Ganymede...
Q1)At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 ....
Q1)At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 47.0 N at the surface of the earth. In this problem, use 9.81 m/s2 for the acceleration due to gravity on earth. a-What is its mass on the earth's surface? b-What is its mass on the surface of Io? c-What is its weight on the surface of Io? ---------------------------------------------------------------------- Q2)The upward normal force exerted by the floor is...
Your acceleration due to gravity is g/ 2. How high are you above the Earth's surface?...
Your acceleration due to gravity is g/ 2. How high are you above the Earth's surface? h=______m
At what distance above the surface of the earth is the acceleration due to the earth's...
At what distance above the surface of the earth is the acceleration due to the earth's gravity 0.825 m/s2 if the acceleration due to gravity at the surface has magnitude 9.80 m/s2?
A satellite of mass 3.00 x 104 kg is placed in orbit 5.00 x 105 m...
A satellite of mass 3.00 x 104 kg is placed in orbit 5.00 x 105 m above the surface of Jupiter. Please refer to the data table for planetary motion included in this lesson. Determine the force of gravitational attraction between the satellite and Jupiter. What must be the orbital speed of the satellite? What must be the value of the gravitational field constant, g, at the location of the satellite? One of the moons of Jupiter is Europa. It's...
For a spherical celestial object of radius R, the acceleration due to gravity g at a...
For a spherical celestial object of radius R, the acceleration due to gravity g at a distance x from the center of the object is g = g0R2/x2, where g0 is the acceleration due to gravity at the object's surface and x > R. For the moon, take g0 = 1.63 m/s2 and R = 3200 km. If a rock is released from rest at a height of 5R above the lunar surface, with what speed does the rock impact...
Near the surface of the Earth, the magnitude of the acceleration due to gravity is 32...
Near the surface of the Earth, the magnitude of the acceleration due to gravity is 32 ft/s^2. A projectile is shot vertically upward from ground level with an initial velocity of 96 ft/s. A. What is the velocity at t=1 s? B. What is the maximum height attained by the projectile? C. How long is the projectile in the air? D. What is the impact velocity?
Objects near Earth fall due to gravity. The acceleration of an object due to gravity. The...
Objects near Earth fall due to gravity. The acceleration of an object due to gravity. The acceleration of an object due to gravity is then x" = g, where x represents the distance above the ground and g = (wave; about same) -9.8m/s(^2) a. Find the general solution to the equation b. Given the initial data x(0) = 0 and x'(0) = 1, find the particular solution c. Plot your solution over a meaningful range of time d. When is...
(a) At what height above the earth is the acceleration due to gravity 62% of its...
(a) At what height above the earth is the acceleration due to gravity 62% of its value at the surface? (b) What is the speed of a satellite orbiting at that height? I got 1210.49km for question a by using the formula, but it is wrong.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT