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A car goes around a curve of radius r at a constant speed v. Then it...

A car goes around a curve of radius r at a constant speed v. Then it goes around another curve of radius 3r at speed the same speed. What is the centripetal acceleration on the car as it goes around the second curve, compared to the first?

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Answer #1

given

radius of second curve = r = 3r

speed = v = 3v

Original centripetal acceleration = v2 /r

New acceleration = (3v)2 / 3r

                            = 9 v2 / 3r

                            = 3 (v2 / r)

So the new acceleration is thrice as big as the original acceleration,

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