Determine the current in the 12-Ω resistor for the circuit shown in the figure assuming that the batteries are ideal.
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That is the image
Here we have given that,
Two emf sources 6 V and 9 V and are ideal means no internal resistance.
And two resistor connect here 18 ohm and 12 ohm
We have to find the current through the 12 ohm resistor.
Here as the 18 ohm and combination of 6v and 12 v are connected in parallel with each other so they will have same voltage source so that,
So for that we can use here nodal analysis we will get the following equation as,
I = 9-6/12 = 3/12 = 0.25 A
Hence current through the 12 ohm resistance will be 0.25 A
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