Question

A slender, 400- g bar magnet 10.0 cm long has a magnetic moment of 5.60 A m2. It is held at an angle of 45 o to the direction of a uniform magnetic field. When released, it begins to rotate about its center with an initial angular acceleration of 5.35e3 rad/s2. What is the magnitude of the magnetic field?

Answer #1

The magnetic field B exerts a torque ? on a magnetic dipole, which has a magnetic moment M. This torque produces an angular acceleration ? on the bar about its center, which is determined by its moment of inertia I.

Equations and Calculations:

The torque ? exerted by a magnetic field B on a magnetic dipole having magnetic moment M is given by [see Source 2]:

(1) ? = M X B

= M * B * sin (?),

where:

? = the angle between the magnetic moment (aligned with the bar
axis) and B = 45

The uniform thin rod in the figure below has mass M =
2.00 kg and length L = 2.87 m and is free to rotate on a
frictionless pin. At the instant the rod is released from rest in
the horizontal position, find the magnitude of the rod's angular
acceleration, the tangential acceleration of the rod's center of
mass, and the tangential acceleration of the rod's free end.
HINT
An illustration shows the horizontal initial position and
vertical final position...

1. A person pushes on a doorknob with a force of 5.00 N
perpendicular to the surface of the door. The doorknob is located
0.800 m from the axis of the hinges of the door. The door begins to
rotate with an angular acceleration of 2.00 rad/s2. What
is the moment of inertia of the door about hinges?
Select one:
a. 6.50 kg.m2
b. 2.50 kg.m2
c. 12.5 kg.m2
d. 2.00 kg.m2
2. A dumbbell has a connecting bar of...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 15 minutes ago

asked 15 minutes ago

asked 17 minutes ago

asked 23 minutes ago

asked 30 minutes ago

asked 34 minutes ago

asked 51 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago