Question

A -2.8nC charge is on the x-axis at x1 = -8cmand a 3.5nC charge is on the x-axis at x2 = 16cm. At what point or points on the y-axis is the electric potential zero?

Answer #1

**let the potential be zero at y units from
origin**

**so this y is at distance of sqrt ( y^2 + 0.0064) units
from -2.8 nC**

**or this point is at a distance of (sqrt(Y^2 + 0.0256)
from 3.5 nC charge**

**for potential to be zero, potential due to both charges
must be same**

**potential due to a point charge is given by V =
Kq/r**

**here V1 = V2**

**Kq1/sqrt (y^2+ 0.0064) = Kq2/sqrt ( y^2 +
0.0256)**

**sqrt {(Y^2 + 0.0256)/(Y^2 + 0.064)} = 3.5/2.8 =
1.25**

**{(Y^2 + 0.0256)/(Y^2 + 0.064)}= 1.25^2 =
1.5625**

**Y^2 + 0.0256 = 1.5625Y^2 + 0.1**

**Y^2( 0.5625) = 0.0744**

**Y^2 = 0.1322**

**Y = +- 0.3636 m**

**so at a distance on either + 36 cm or - 36cm on Y axis net
potential is zero**

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