A railroad freight car, mass 20 000 kg, is allowed to coast along a level track at a speed of 2.0 m/s. It collides and couples with a 50 000-kg loaded second car, initially at rest and with brakes released. What percentage of the initial kinetic energy of the 20 000-kg car is preserved in the two-coupled cars after collision?
Question 10 options:
14% |
|
23% |
|
29% |
|
31% |
Mass of the first car = m1 = 20000 kg
Mass of the second car = m2 = 50000 kg
Initial speed of the first car = V1 = 2 m/s
Initial speed of the second car = V2 = 0 m/s (At rest)
Speed of both the cars after the collision = V3
By conservation of linear momentum,
m1V1 + m2V2 = (m1 + m2)V3
(20000)(2) + (50000)(0) = (20000 + 50000)V3
V3 = 0.5714 m/s
Initial kinetic energy of the system = KE1
KE1 = m1V12/2
KE1 = (20000)(2)2/2
KE1 = 40000 J
Final kinetic energy of the system = KE2
KE2 = (m1 + m2)V32/2
KE2 = (20000 + 50000)(0.5714)2/2
KE2 = 11427.43 J
Percentage of the initial kinetic energy preserved = P
P = 29%
Percentage of the initial kinetic energy preserved in the two coupled cars after the collision = 29%
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