Question

Part A

What is the escape speed from an asteroid of diameter 265 km with a density of 2410 kg/m3?

Express your answer in meters per second.

Answer #1

Gravitational constant = G = 6.67 x 10^{-11}
N.m^{2}/kg^{2}

Density of the asteroid = = 2410
kg/m^{3}

Diameter of the asteroid = D = 265 km = 265000 m

Radius of the asteroid = R = D/2 = 265000/2 = 132500 m

Volume of the asteroid = V

V = 9.744 x 10^{15} m^{3}

Mass of the asteroid = M

M = V

M = (2410)(9.744x10^{15})

M = 2.348 x 10^{19} kg

Escape velocity from the asteroid = V_{e}

V_{e} = 153.75 m/s

A) Escape speed from the asteroid = 153.75 m/s

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