Part A
What is the escape speed from an asteroid of diameter 265 km with a density of 2410 kg/m3?
Express your answer in meters per second.
Gravitational constant = G = 6.67 x 10-11 N.m2/kg2
Density of the asteroid = = 2410 kg/m3
Diameter of the asteroid = D = 265 km = 265000 m
Radius of the asteroid = R = D/2 = 265000/2 = 132500 m
Volume of the asteroid = V
V = 9.744 x 1015 m3
Mass of the asteroid = M
M = V
M = (2410)(9.744x1015)
M = 2.348 x 1019 kg
Escape velocity from the asteroid = Ve
Ve = 153.75 m/s
A) Escape speed from the asteroid = 153.75 m/s
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