Question

In the figure, a conducting rod of length L = 27.0 cm moves in a magnetic field B of magnitude 0.350 T directed into the plane of the figure. The rod moves with speed v = 5.00 m/s in the direction shown. (Figure 1)

1.When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?

Express your answer in volts per meter to at least three significant figures.

2. What is the magnitude Vba of the potential difference between the ends of the rod?

Express your answer in volts to at least three significant figures.

3.What is the magnitude E of the motional emf induced in the rod?

Express your answer in volts to at least three significant figures.

Answer 1

Hence
q*v*B = q*E
E = v*B
E = 5*0.38 = 1.9V/m Ans.1
Question2-----------------
emf V = E*d
d = 33cm = 0.33m
V = 1.9*0.33
V = 0.627V Ans.2
Question3--------------
It is same as question1

here,
length of rod, l = 27 cm = 0.27 m
velocity , v = 5 m/s
magnatic field, B = 0.350 T

Lortez's force = electric force
q * v * B = q * E

Part a:
electric field, E = v * B
electric field, E = 5 * 0.350
electric field, E = 1.75 V/m

Part b:
Electric potential, V = E*l
Electric potential, V = 1.75*0.27
Electric potential, V = 0.472 V

Part c:
motional emf , EMF = B * l * v
motional emf , EMF = 0.350 * 0.27 * 5
motional emf , EMF = 0.472 V