A circular loop in the plane of the paper lies in a 0.78 T magnetic field pointing into the paper.
A) What is the magnitude of the average induced emf? Answer in V.
B) If the coil resistance is 4.3 ohm , what is the average induced current? Answer in A
I think you have missed the other information mentioned in the problem. I think the missing information should be the loop diameter changes from d1 to d2 in time t seconds.
You have given the value of B = 0.78 T
So, for the part (A) -
The expression of the induced emf is -
V = dø / dt = 0.78 . ( ? . (d1/2)^2 – ? .(d2/2)^2 ) / t
put the values of d1, d2 and t, you will get the result.
For the part (B) -
Coil resistance R = 4.3 Ohm
So, avearge induced current I = V / R = (put the value of V calculated in part A) / 4.3
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