Question

A) How long does it take the ball to reach the maximum height?

Answer #1

write your givens:

Vf
= 0 m/s ( this is when the ball is at its highest
point)

Vi = 18 m/s (given quantity)

a = -9.81 m/s^2 (the ball is travelling against the pull of
gravity.gravity will sooner or later pull the ball back
down)

d = ? (the variable you're trying to find)

Vf^2 = Vi^2 + 2ad (isolate for d)

d = Vf^2 - Vi^2/ 2(a) (distance equals final velocity squared
minus
initial velocity
squared, divided by twice the acceleration)

d = (0 m/s)^2 - (18 m/s)^2 / 2(-9.81 m/s^2)

d = 16.5 m to the nearest tenth or 17 m to the nearest
one.

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