Question

A laser emits a beam of light who’s photons all have the same frequency. When the beam strikes the surface of the metal, photoelectrons are ejected from the surface. What happens if the laser emits twice the number of photons per second?

1. The photoelectrons are ejected from the surface with twice the maximum kinetic energy.
2. The photoelectrons are ejected from the surface with the same maximum kinetic energy
3. The number of photoelectrons ejected per second are doubled.
4. Both b and c
5. Both a and c

Answer 1

option D)

The maximum kinetic energy of the ejected photoelectrons depends only on the energy of the photon and the energy of the photon is frequency-dependent .since frequency remains the same so energy of photon does not change .So doubling the no of photons per sec does not change energy so photoelectrons will eject from the surface with the same maximum kinetic energy.

Now If we double the no of photons that strike the surface means that photoelectrons ejected per second are doubled.

so both b and c correct