Two particles with charges +8e and -8e are initially very far apart (effectively an infinite distance apart). They are then fixed at positions that are 5.05 x 10-12 m apart. What is EPEfinal - EPEinitial, which is the change in the electric potential energy?
electric potential energy is given by:
EPE = k*q1*q2/r
So,
EPE_final - EPE_initial = k*q1*q2/r_f - k*q1*q2/r_i = k*q1*q2*(1/r_f - 1/r_i)
r_i =
r_f = final separation between both charges = 5.05*10^-12 m
q1 = +8e, q2 = -8e
Using given values:
EPE_final - EPE_initial = 9*10^9*8e*(-8e)*(1/(5.05*10^-12) -
1/)
EPE_final - EPE_initial = -9*10^9*64*(1.6*10^-19)*(1/(5.05*10^-12) - 0)
EPE_final - EPE_initial = -2.92*10^-15 J
Let me know if you've any query.
Get Answers For Free
Most questions answered within 1 hours.