At time t=2.3 s, a 4-kg block that initially moves with a constant speed of 6 m/s undergoes an inelastic collision with another block. Any two inertial observers must agree that...
Ans -
A , B , C , E
A- Event took place at given time as mentioned in question
B - as given the speed is constant so the initial speed is 6 m/ s
C momentum = mass x velocity
= 6 x 4 = 24
D- second block will move or not it can't be said it depends on the mass of the block if the mass is high inertia will be high and the first block will rebound after collision and second will not move if force imparted after collision is not enough to counter the mass inertia of second block
E - in both elastic and inelastic collision the momentum remains conserved so this fact will also be true but in inelastic collision the kinetic energy will not be remains constant .
Get Answers For Free
Most questions answered within 1 hours.