A person has a far point of 27 cm and a near point of 12 cm. Her eyeglasses are 2 cm from her eye. What power lenses must be prescribed to correct this person's vision?
since this eye can already focus on objects locatde at thenear point of a normal eye,no correction is needed for near
objects.To correct the distant vision , a corrective lens(located 2cm from the eye) should form virtual images of very
distant objects at 27 cm in front of the lens.thus we have q =-(27-2) = -25 cm & P------>∞
thus we have
1/f = 1/p + 1/q
= 0+1/-25 cm
or
f= -25 cm
refractive power is P = 1/-0.25m
= - 4 diopters.
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