Question

A chair of weight 140 N lies atop a horizontal floor; the floor is not frictionless....

A chair of weight 140 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 38.0 N directed at an angle of 38.0 ∘ below the horizontal and the chair slides along the floor.

1.Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.

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Answer #1

Since, the force exerted on the chair is not completely horizontal, there will be a component of force which will push the chair down. So, the total downward force exerted by chair on the ground will be the sum of its weight and this component of non horizontal force. And this total downward force will be equal to the total normal force:

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