Question

A gas, while expanding under isobaric conditions, does 481 J of work. The pressure of the gas is 1.72E+5 Pa, and its initial volume is 1.35E-3 m3. What is the final volume of the gas?

Answer 1

Solution:

W = 481 J

P = 1.72 x 10⁵ Pa

V_i = 1.35 x 10^-3 m³

Since: The work done by a gas under isobaric condition is : W = P V
Where P is the constant pressure and V is the change in volume
W = P (V_f  - V_i)
V_f  = (W / P) + V_i
V_f  = (481 J / 1.72 x 10⁵ Pa) + 1.35 x 10^-3
V_f  =   2.796 x 10^-3  +  1.35 x 10^-3
V_f  = 4.146 x 10^-3 m³