Question

How much heat is required to change a 47.8 g ice cube from ice at -10.4°C to water at 80°C? (if necessary, use c_ice=2090 J/kg°C and c_steam= 2010 J/kg°C)

How much heat is required to change a 47.8 g ice cube from ice at -10.4°C to steam at 110°C?

Answer 1

here,

mass of ice , m = 47.8 g = 0.0478 kg

the heat energy required , Q = m * ( Ci * ( 0 - (-10.4)) + Lf + Cw * ( 80 - 0))

Q = 0.0478 * ( 2090 * 10.4 + 334000 + 4186 * 80) J

Q = 3.3 * 10^4 J

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mass of ice , m = 47.8 g = 0.0478 kg

the heat energy required , Q' = m * ( Ci * ( 0 - (-10.4)) + Lf + Cw * ( 100 - 0) + Lv + Cs * ( 110 - 100))

Q' = 0.0478 * ( 2090 * 10.4 + 334000 + 4186 * 100 + 2256000 + 2010 * 10) J

Q' = 1.46 * 10^5 J