Question

Consider a sheet of paper 8.05 in by 11.45 in. Part (a) How much force, in...

Consider a sheet of paper 8.05 in by 11.45 in.

Part (a) How much force, in newtons, is exerted on one side of the paper by the atmosphere?

Part (b) The mass of a mid-sized car is about 1000 kg. What is the ratio of the weight of a car to the force of the atmosphere on this piece of paper?

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Homework Answers

Answer #1

Given data:

Area of sheet paper,

A = l x b

l = 8.05 in

l = 0.20447 m

b = 11.45 inch

b = 0.29083 m

A = l x b

= 0.20447 x 0.29083

A = 0.0594660101 m2

(a)

How much force, in newtons, is exerted on one side of the paper by the atmosphere?.

F = P/A

P = atmospheric pressure

P =  1.01325 x 105 Pa

F = 1.01325 x 105/ 0.0594660101

F = 17.0391455269 x 105 N

F = 17.039 x 105 N

(b)

Mass of car , m = 1000 kg

W = mg

= 1000 x 9.8

W = 980 N

Ratio = weight of car / Force on sheet of paper

= 980/ 17.039 x105

= 57.51511 x 10-5

ratio = 0.0057

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