Question

One mole of an ideal gas initially at a temperature of T_i = 5.6°C undergoes an expansion at a constant pressure of 1.00 atm to nine times its original volume.?

(a) Calculate the new temperature T_f of the gas.

_____ K

(b) Calculate the work done on the gas during the expansion.?

_____kJ

Answer 1

given

n = 1 mole
Ti = 5.6 C = 5.6 + 273 = 278.6 K
Pi = 1 atm = 1.013*10^5 pa
Vf = 9*Vi

a) at constant temperature V/T = constant

Vi/Ti = Vf/Tf

Tf = Ti*(Vf/Vi)

= Ti*(9*Vi/Vi)

= Ti*9

= 278.6*9

= 2507 K <<<<<<<<-------------------Answer

b) Workdone done by the gas during expansion, W = P*(Vf - Vi)

= P*(9*Vi - Vi)

= 8*P*Vi

= 8*n*R*Ti (since P*V = n*R*T)

= 8*1*8.314*278.6

= 18530 J

= 18.5 kJ <<<<<<<<-------------------Answer