Question

1. How much energy would it take to vaporize an ice cube at -10 C? (Note: you’ll have to look up any constants and list the constants used in your calculations.)

Answer 1

Solution:

For a block of ice to vaporizer,

Energy required to vaporize an ice cube = Heat released going from -10^oC to 0^oC + Phase chance from ice to water + Heat released by water from 0^oC to 100^oC + Phase change of water to vapour

= 2.04*10³ J/kgK* [0^o - 10^oC] + 335*10³ J/kg + 4180 J/kg-K*[100^oC - 0^oC] + 2,260*10³J/kg

= 2.04*10⁴ + 335*10³ + 4180*10² + 2260*10³

= 3033400 J/kg

= 3.03*10⁵ J/kg.

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