Question

1. Todd and Susan are riding on a merry-go-round. Todd rides on a horse toward the outside of the circular platform, and Susan rides on a horse toward the center of the circular platform. When the merry-go-round is rotating at a constant angular speed, ω –

Todd’s linear speed, v is

(A) exactly half as much as Susan’s.

(B) larger than Susan’s. (C) smaller than Susan’s (D) the same as Susan’s. (E) exactly twice as much as Susan’s.

use diagram to explain answer

Answer 1

Since in this question the position of Susan with respect to position of Todd is not given ( i.e, one fouth distance or half the distance OT)

However I have solved it by Assuming that The position of Susan is exactly the half of the position of Todd.

v_s^=(OS) × omega = linear velocity of Susan

V_o= (OT) × omega = linear velocity of Todd