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Electrons are accelerated through a voltage difference of 235 kV inside a high voltage accelerator tube....

Electrons are accelerated through a voltage difference of 235 kV inside a high voltage accelerator tube.

What is the final kinetic energy of the electrons?
2.35×105 eV

What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.)

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Answer #1

kinetic energy of the electrons = eV = 1.6x10-19 x 235 x 103 Jouls = 3.76x10-14 jouls

kinetic energy of the electrons in eV = 1.6x10-19 x 235 x 103 Jouls / 1.6x10-19 = 235x103 ev = 2.35x105 ev Ans

kinetic energy of the electrons = 1/2 mv2 =   3.76x10-14 jouls speed of electron =

speed of electron   = 2.87x108 m/s

speed of electrons in terms of the speed of the light =  2.87x108 m/s/3x108m/s = 0.957C Ans

where C is the speed of light

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