Question

A satellite is orbiting Earth 1,790 m above Earth's surface.
Earth has a mass of 5.97×10^{24} kg and a radius of
6371×10^{3} m. What is the satellite's speed? Answer in SI
units, rounded to the nearest whole number.

Thank youuuu

Answer #1

This problem is solved with help of concept of circular motion. The earth will attract the satellite orbiting around the earth. The gravitational attraction will be balance by the centrifugal force produced by orbiting satellite. The force will be balance. So the gravitational attraction is equal to centrifugal force.

Answer: the velocity of satellite is 8 km/s.

A 160 kg satellite is orbiting on a circular orbit 7655 km above
the Earth's surface. Determine the speed of the satellite. (The
mass of the Earth is 5.97×1024
kg, and the radius of the Earth is 6370 km.)
(in km/s)

A 345 kg satellite is orbiting on a circular orbit 8955 km above
the Earth's surface. What is the gravitational acceleration at the
location of the satellite? (The mass of the Earth is
5.97×1024 kg, and the radius of the Earth is 6370
km.)?

A satellite (mass 2400 kg) is orbiting the Earth, with a speed
of 7500 m/s. What is the height of this satellite above the Earth's
surface?
Note: you may find the following information useful. The
universal gravitational constant is 6.67x10-11
Nm2/kg2 ; the mass of the Earth is 6.0 x
1024 kg; the radius of the Earth is 6.4 x 103
km.
can you please show work if you can? I APPRECIATE YOU!!!

NASA launches a satellite into orbit at a height above the
surface of the Earth equal to the Earth's mean radius. The mass of
the satellite is 830 kg. (Assume the Earth's mass is 5.97 1024 kg
and its radius is 6.38 106 m.) (a) How long, in hours, does it take
the satellite to go around the Earth once? h (b) What is the
orbital speed, in m/s, of the satellite? m/s (c) How much
gravitational force, in N,...

A satellite is set to orbit at an altitude of 20200 km above the
Earth's surface. What is the period of the satellite in hours?
(Earth radius 6.378×1066.378×106 m, Earth mass 5.97×10245.97×1024
kg, Universal Gravitational constant
G=6.67×10−11m3kg−1s−2G=6.67×10−11m3kg−1s−2 ).

Determine the distance above Earth's surface to a satellite that
completes two orbits per day. (Earth's mass is 5.97 x 1024 kg and
its radius is 6.38 x 106 m)

A satellite of mass 180 kg is placed into
Earth orbit at a height of 700 km above the surface.
(a) Assuming a circular orbit, how long does the
satellite take to complete one orbit?
h
(b) What is the satellite's speed?
m/s
(c) Starting from the satellite on the Earth's surface, what is the
minimum energy input necessary to place this satellite in orbit?
Ignore air resistance but include the effect of the planet's daily
rotation.

A satellite of mass m = 2.00 ×103 kg is launched into a
circular orbit of orbital period T = 4.00 hours. Newton's
gravitational constant is G = 6.67 ×10−11 N∙m2/kg2, and
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What is the total mechanical energy (kinetic energy + potential
energy) of the satellite in orbit? Take the gravitational potential
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A 565-kg satellite is in a circular orbit about Earth at a
height above Earth equal to Earth's mean radius.
(a)
Find the satellite's orbital speed.
_____ m/s
(b)
Find the period of its revolution.
_____h
(c)
Find the gravitational force acting on it.
_____N

1)
Two celestial objects are in space: one with a mass of 8.22 x 109
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attraction (in newtons) between the objects? Round to the nearest
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mass of 6.42 x 1023 kg, what will its free-fall...

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