Question

An ideal gas goes through the following two-step process. 1) The container holding the gas has...

An ideal gas goes through the following two-step process. 1) The container holding the gas has a fixed volume of 0.240 m3 while the pressure of the gas increases from 2.00×105 Pa to 4.00×105 Pa . 2) The container holding the gas is then compressed to a volume of 0.150 m3 while maintaining a constant pressure of 4.00×105 Pa .

Part A

What is the total work done by the gas for this two-step process?

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Answer #1

Work done by the gas is area under the P-V diagram. We need to plot the curve and find the area under the curve in P-V diagram and take care of the units of pressure and volume. Here, both of them are in SI units hence, we didn't make any mistake.

The work done by the gas is 36kJ. The work done on the gas would have been negative if the cycle is directed anti clockwise, which is the case here, hence, work done by the gas is positive.

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