Question

A crate of fruit with a mass of 35.0 kg and a specific heat capacity of 3800 J/(kg⋅K) slides 8.40 m down a ramp inclined at an angle of 36.1 degrees below the horizontal.

Part A: If the crate was at rest at the top of the incline and has a speed of 2.65 m/s at the bottom, how much work Wf was done on the crate by friction? Use 9.81 m/s2 for the acceleration due to gravity and express your answer in joules.

Answer #1

Given data:

mass = 35 kg

heat capacity = 3800 J/ Kg.K

sliding down = 8.40 m

angle = 36.1 degrees

speed = 2.65 m/s

g= 9.81 m/s^2

Work done by friction can be found as the difference of potential energy and kinetic energy.

Potential energy change: mgh = mgs sin 36.1°.

Kinetic energy change: ½ mv².

Work done by friction (on crate): mgs sin 36.1° − ½ mv²

W = 35*(9.8 *8.40* sin 36.1 − ½ * 2.65²) = 1574 J.

For a frictionless incline surface, potential energy change =
kinetic energy change, along with null friction work. In the
present case, however,

kinetic energy is only about 7% of potential energy: almost 93%
of

energy is converted to heat.

A crate of fruit with a mass of 33.5 kg and a specific heat
capacity of 3800 J/(kg?K) slides 8.30 m down a ramp inclined at an
angle of 37.4 degrees below the horizontal.
If the crate was at rest at the top of the incline and has a
speed of 2.20 m/s at the bottom, how much work Wf was done
on the crate by friction?
Use 9.81 m/s2 for the acceleration due to gravity and express
your answer...

A crate of fruit with a mass of 31.0 kg and a specific heat
capacity of 3600 J/(kg?K) slides 7.60 m down a ramp inclined at an
angle of 36.8 degrees below the horizontal.
If the crate was at rest at the top of the incline and has a
speed of 2.05 m/s at the bottom, how much work Wf was done
on the crate by friction?
Use 9.81 m/s2 for the acceleration due to gravity and express
your answer...

A crate of fruit with a mass of 39.0 kg and a specific heat
capacity of 3600 J/(kg⋅K) slides 8.70 m down a ramp inclined at an
angle of 38.3 degrees below the horizontal.
Part A If the crate was at rest at the top of the incline and
has a speed of 2.65 m/s at the bottom, how much work Wf was done on
the crate by friction? Use 9.81 m/s2 for the acceleration due to
gravity and express...

A crate of fruit with a mass of 35.0 kg and a specific heat
capacity of 3800 J/(kg⋅K) slides 8.40 m down a ramp inclined at an
angle of 36.1 degrees below the horizontal.
If an amount of heat equal to the magnitude of the work done by
friction is absorbed by the crate of fruit and the fruit reaches a
uniform final temperature, what is its temperature change
ΔT?

A worker wants to load a 12 kg crate into a truck by sliding the
crate up a straight ramp which is 2.5 m long and which makes an
angle of 30 degrees with the horizontal. The worker believes that
he can get the crate to the very top of the ramp by launching it at
5 m/s at the bottom. Note that the worker does not keep pushing on
the crate. But the worker underestimated or even forgot about...

Beginning from rest, an object of mass 200 kg slides down a
9-m-long ramp. The ramp is inclined at an angle of 20o
from the horizontal. Air resistance and friction between the object
and the ramp are negligible. Let g = 9.81
m/s2.
Determine the kinetic energy of the object, in kJ, and the velocity
of the object, in m/s, at the bottom of the ramp.

A crate with a mass of 3.00 kg starts from rest at the top of a
28.0° incline and slides 2.00 m down the incline in 1.25 s.
(a) What is the magnitude of the acceleration of the crate (in
m/s2)?
2.56 m/s2 correct
b) What is the frictional force (in N) acting on the crate?
(Enter the magnitude.)
(c) What is the coefficient of kinetic friction between the
crate and the incline?
(d) What is the speed of the...

You are pulling a
heavy crate (mass m) up a ramp inclined at an angle
θ to the horizontal. The ramp is not a smooth
surface. The rope that you are pulling with is parallel to the
incline.
What forces are acting
on the crate?
Group of answer choices
Friction, gravity, normal force and tension
Gravity and tension
Friction, gravity and tension
Friction
Gravity, normal force and tension
Gravity
Normal force
Tension

This time we have a crate of mass 42.4 kg on an inclined
surface, with a coefficient of kinetic friction 0.139. Instead of
pushing on the crate, you let it slide down due to gravity. What
must the angle of the incline be, in order for the crate to slide
with an acceleration of 5.96 m/s^2?

This time we have a crate of mass 43.5 kg on an inclined
surface, with a coefficient of kinetic friction 0.102. Instead of
pushing on the crate, you let it slide down due to gravity. What
must the angle of the incline be, in order for the crate to slide
with an acceleration of 5.28 m/s^2?

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 17 minutes ago

asked 23 minutes ago

asked 30 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago