Question

A proton is placed in a uniform electric field of 2600N/C .

Calculate the magnitude of the electric force felt by the proton.

Calculate the proton's acceleration.

Calculate the proton's speed after 1.10 μs in the field, assuming it starts from rest.

Answer 1

A proton is placed in a uniform electric field of 2600N/C .

the magnitude of the electric force felt by proton is
= 1.6 X 10^-19 X 2600

=4160 X 10^-19 N

proton's acceleration is

F = m a

a = force (F) / mass(m)

acceleration (a) = 4160 X 10^-19 / 1.6726 X 10^-27

acceleration (a) = 2491 X 10⁸ m/s²

the proton's speed after 1.10 μs in the field,

then speed can be written as

= v = at

= 2491 X 10⁸ X 1.10 X 10^-6

the speed after 1.10 μs is = 2740.1 X 10² m/s

or

= 2.7401 X 10⁵ m/s