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A steel ball with mass 1.45 kg rolls down an incline into a loop-the-loop of radius...

A steel ball with mass 1.45 kg rolls down an incline into a loop-the-loop of radius R = 1.8 m. At what minimum vertical height in m above the ground H must the ball be released in order for the ball to stay on the track at the top of the loop?

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Answer #1

The Radius of the Ball is not given so we will be assuming it to be 'r' and the this value is very much lower than the Radius of the Loop 'R' .

I have solved the problem including the rotational Kinetic Energy of the ball. This problem can also be solved by neglecting Rotational Kinetic Energy since r<<R.

Therefore,

The minimum vertical height above the ground where the ball must be released in order for the ball to stay on the track at the top of the loop is 4.5m.

Hope this helps!!

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