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A 1.10 KeV kinetic energy positron penetrates a region where there is a uniform magnetic field...

A 1.10 KeV kinetic energy positron penetrates a region where there is a uniform magnetic field of 0.16 T at an angle of 85.99 degrees. Determine the radius of the helical path?

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Answer #1

Let v is the velocity and m is the mass of the positron

Component of the velocity due to which positron moves in circular part of the helix = vsin85.99°

Magnetic field B = 0.16 T

Charge on the positron q = 1.6 × 10-19 C

Mass of the positron m = 9.1 × 10-31 kg

Kinetic energy of the positron E = 1.1 keV = 1.1 × 1.6 × 10-16 J

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