Question

An airplane is flying with a velocity of 240 m/s at an angle of 30.0 degrees with the horizontal, as the drawing shows. When the altitude of the plane is 2.4 km, a flare is released from the plane. The flare hits the target on the ground. What is the angle theta?

Directions: In order to find the angle theta, you need to find its tan. From the diagram you need to find the adjacent side to find tan(theta). SPlit the motion of the flare into x,y components and look at them separately. Find the time spent in the air from one of these y components (using the formula for a quadratic equation) and then use this time t spent in the air into the x component of the motion. - please show formulas and steps how you would get the answer this way!

Answer 1

U need tofind the horizontal distance from the air plane to the targetin order to find the angle.

X_f = V_xit
X_f = (240 cos 70) t

we dont have the value of t. keep the equation and proceed


find the time of the projectile.

Y_f = V_yit + 1/2a_yt²

2400 = (240 sin 30)t + 1/2(9.8)t²
findvalue of t



insert the t into the first equation

X_f = (240 cos 30)(t)
     =..........m



         2500m    
                                            2911.4m

find angle
tan? = 2500/2911.4
   ? = 40.65 degrees