Question

An object with a height of 4.0 cm is at a position of 6.0 cm in front of a converging lens. The image inverts and is at a position 3.0 cm from the lens. The image height is Answer: 2.0 cm

Answer 1

here, image distance,

d_i = 3 cm

object distance is,

d_o = -6 cm

so, magnification is,

m = d_i/d_o = (3 cm)/(-6 cm)

= -0.5

now, image height is h_i, and object height is h_o = 4 cm and

m = h_i/h_o

or, -0.5 = h_i/(4 cm)

or, h_i = -2 cm

hence the image height is 2 cm. (minus sign before image height indicates the the image is inverted.)

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