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An initially uncharged air-filled capacitor is connected to a 2.01 V charging source. As a result,...

An initially uncharged air-filled capacitor is connected to a 2.01 V charging source. As a result, the capacitor acquires 5.49×10−5 C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant ? of this substance is 7.11. Find the voltage ? across the capacitor and the charge ?f stored by it after the dielectric is inserted and the circuit has returned to a steady state.

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Answer #1

Initially

V= 2.01 V

Q= 5.49 * 10-5 C

We know that

If a dielectric slab is filled of k=7.11 so

Since the capacitor is connected to same source so voltage will be same, that is

Now,

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