The three forces shown in the figure below act on a particle (with F1 = 46.0 N, F2 = 59.0 N, θ1 = 61.0°, and θ2 = 29.0°). If the particle is in translational equilibrium, find F3, the magnitude of force 3 and the angle θ3.
The figure is not shown here. But I will try to explain.
The forces are given as,
F1 = 46.0 N,
F2 = 59.0 N,
θ1 = 61.0°,
and θ2 = 29.0°
I think the the first two are in the same quadrant since the angles are less than 900.
F3cosθ3 = F1cosθ +
F2 cosθ1
=>F3cosθ3 = 46cos610 +
59cos290
=>F3cosθ3 = 73.90
----------------(i)
& F3sinθ3 =
F1sinθ1- F2sinθ2
=>F3sinθ3 = 46sin610 -
59sin290
=>F3sinθ3 = 11.63 --------------(ii)
=>F3 = [(73.9)2
+ (11.63)2]
=>F3 = 74.8 Newton
& By (ii)/(i):-
=>θ =tan-1( 11.63/73.9 )= 8.92
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