Question

A hydrogen atom is in its ground state

(n_{i} = 1)

when a photon impinges upon it.

The atom absorbs the photon, which has precisely the energy required to raise the atom to the

n_{f} = 3

state.

(a)

What was the photon's energy (in eV)?

eV

(b)

Later, the atom returns to the ground state, emitting one or more photons in the process. Which of the following energies describes photons that might be emitted thus? (Select all that apply.)

10.2 eV 12.1 eV 1.89 eV 13.6 eV

Answer #1

A hydrogen atom in the ground state absorbs a 12.75 eV photon.
Immediately after the absorption, the atom undergoes a quantum jump
to the next-lowest energy level.
What is the wavelength of the photon emitted in this quantum
jump?
Express your answer using four significant figures.
I've seen this question before, but I'm looking the wavelength, not
the energy, or n. Thanks!

A
ground state hydrogen atom absorbs a photon light having a
wavelength of 92.57 nm. It then gives off a photon having a
wavelength of 1944 nm. What is the final state of the hydrogen
atom?
I got Nf=1.14 and it wasn't right

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please try to show solution

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