Question

Two oppositely charged identical insulating spheres, each 59.0cm in diameter and carrying a uniform charge of magnitude 165?C , are placed 1.20m apart center to center.

If a voltmeter is connected between the nearest points on their surfaces, what will it read?

Answer #1

The amount of charge that can be placed on a capacitor is
proportional to the voltage pushing the charge onto the positive
plate. The larger the potential difference (voltage) between the
plates, the larger the charge on the plates:

**Q = C V**

The constant of proportionality is called the "capacitance" and is
proportional to the area (A) of one of the plates and inversely
proportional to the separation between the plates (d):

**C = e A / d**

for a parallel plate capacitor,

where e is the permittivity of the insulating material (or
DIELECTRIC) between the spheres.

e = 1.0059

A = area = 4*pi *r*r = 4*3.14 *59/2 *59/2

A= 10930.34 cm ^2

d = 120cm

C = 1.0059 *10930.34 /120

C = 91 mic ro Farad

V = Q/C = 165 / 91 = 1.8 V

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