Question

The force in newtons acting on a kg mass is
Fx=16x^{3}-9x^{2}+8x+14 where x is in meters. Fx is
oriented in the x-direction and acts on the 12kg mass from
x_{0}=0 to x_{f}=5m. If initially at rest and all
of the work of Fx is conserved, find the velocity of the 10kg mass
at x_{f}=10m. report results in m/s

=

Answer #1

A force of 720 newtons stretches a spring 4 meters. A mass of 5
kg is attached to the end of the spring and is released from a
position .5 meters below the equilibrium position with a downward
velocity of 8 meters per second. What is the equation of
motion?
Please solve using Differential equations

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1.) A certain region is characterized by a force equation
Fx (x)=8x^3-14x-6, where U is in joules and x is in
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a.) Find the proper units for the 8, 14, and 6.
b.) Find an equation for the potential energy U(x).
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d.) Which of the equilibrium points are stable? Which are
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A mass of 5 kg is moving at 14 m/s in the +x direction and it
collides inelastically with a mass of 7 kg moving in the -x
direction. The collision takes places in 0.38 seconds and the
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DIFFERENTIAL EQUATIONS
1. A force of 400 newtons stretches a spring 2 meters. A mass of
50 kilograms is attached to the end of the
spring and is initially released from the equilibrium position with
an upward velocity of 10 m/s. Find the equation of
motion.
2. A 4-foot spring measures 8 feet long after a mass weighing 8
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A disk with a c of 1/2 about its center, has a mass of 4 kg, and
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A force F= -F0 e(-x/λ ) (where
F0 and λ are positive constants) acts on a particle of
mass m that is initially at x = x0 and moving with
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v(x) = ± ( v02 +
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