Question

A 2-kg object is moving at 3 m/s. A 4-N force is applied for 1s in...

A 2-kg object is moving at 3 m/s. A 4-N force is applied for 1s in the direction of motion and then removed. Calculate the work done by this force.

Please label and show all work since I have no idea what I am doing. Thank you

Homework Answers

Answer #1

Work done = Force * Displacement .

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 2kg object is moving at 3 m/s. A 4 N force is applied in the...
A 2kg object is moving at 3 m/s. A 4 N force is applied in the direction of motion and then removed after the object has traveled an additional 5 m/s. What is initial kinetic energy of the object. What is the final kinetic energy? What is the final speed of the object?
A 15.0 kg object is moving at 8.50 m/s. A constant force then acts on the...
A 15.0 kg object is moving at 8.50 m/s. A constant force then acts on the object for 2.25 seconds, bringing its final velocity to 3.75 m/s in the opposite direction. a. Calculate the impulse acting on the object b. What is the magnitude and direction of the force? c. What is the momentum of the object before and after the force acts?
2.  A 0.768 kg object is moving with a velocity of 2.53 m/s.  A 0.532 kg moving object...
2.  A 0.768 kg object is moving with a velocity of 2.53 m/s.  A 0.532 kg moving object      hits it.  After collision, the 0.768 kg object has a velocity of 3.22 m/s and the 0.532 kg      object has a velocity of 0.636 m/s.  What was the velocity of the 0.532 kg object      before collision?  (All motion is 1-D; friction can be ignored.)
A force is applied to 1.65 kg object moving with a speed of +5.0 m/s over...
A force is applied to 1.65 kg object moving with a speed of +5.0 m/s over a time of =280 milliseconds (msec). If the magnitude of the force changes as a function of time based on the formula Ft = -4.8t^3+0.36t a) At what time does the Force reach a maximum? b) What is the maximum force experienced by the object? c) What function describes the acceleration of the object as a function of time? d) What function describes the...
"The impulse given to a 2-kg object that goes from moving at 3 m/s in the...
"The impulse given to a 2-kg object that goes from moving at 3 m/s in the + x-direction to 7 m/s in the + y-direction in 5 seconds is 8 kg m/s since the impulse equals the change in momentum. The 5 seconds does not enter into a calculation of this impulse." What, if anything is wrong with this description? If anything is wrong, identify it and explain how to correct it. Please include explanation for why the momentum needs...
A force in the negative direction of an x axis is applied for 27 ms to...
A force in the negative direction of an x axis is applied for 27 ms to a 0.40 kg ball initially moving at 14 m/s in the positive direction of the axis. The force varies in magnitude, and the impulse has magnitude 32.4 N*s. What are the ball’s (a) speed and (b)direction of travel just after the force is applied? What are (c) the average magnitude of the force and (d) the direction of the impulse on the ball? PLEASE...
A 2.30-kg object is moving along the x-axis at 1.90 m/s. As it passes the origin,...
A 2.30-kg object is moving along the x-axis at 1.90 m/s. As it passes the origin, two forces F⃗ 1 and F⃗ 2 are applied, both in the y-direction (plus or minus). The forces are applied for 2.80 s, after which the object is at x = 5.32 m, y = 11.8 m. . i tried 0i-5.077j that is not correct nor is just -5j express anwser in Fx2,please. If F⃗ 1=11.0j^NF→1=11.0j^N, what's F⃗ 2F→2?
A box of mass m = 10 kg sits on a table. The coefficient of kinetic...
A box of mass m = 10 kg sits on a table. The coefficient of kinetic friction is 0.2 between the table and the box. A force of F = 40 N is applied to it horizontally so that the box is moving along the table. a) Calculate the work done by the friction force when the box is displaced 3 m along the direction of its motion. b) What about the work done by the gravitational force? c) The...
A mass of 5 kg is moving at 12 m/s in the +x direction and it...
A mass of 5 kg is moving at 12 m/s in the +x direction and it collides inelastically with a mass of 10 kg moving in the -x direction. The collision takes places in 0.27 seconds and the average force on the mass moving in the +x direction is 170 Newtons in the -x direction. How much total kinetic energy is lost in the collision in Joules? Answer is a positive number since I'm asking how much is lost. please...
A 1-kg ball moving at 5 m/s strikes a 2-kg ball moving at 4 m/s in...
A 1-kg ball moving at 5 m/s strikes a 2-kg ball moving at 4 m/s in the opposite direction. After the collision the 2-kg ball continues moving in the same direction at 1.1 m/s. (a) Find the velocity of the 1-kg ball after the collision. (b) Find the change in the kinetic energy. pls show work