According to Newton´s gravitation law, the acceleration due to gravity is inversely proportional to the square of the distance from the center of the planet. Everest height, RE = 6460 Km + 8.91 Km
You have to calculate the velocity of the satellite if the satellite will rotate in a circular orbit of radius RE. The concept is, the centrifugal force on the satellite is equal to gravitational pull from the planet. Therefore,
7.959 Km/s horizontal velocity would a satellite have to be launched from the top of Mt. Everest to be placed in a circular orbit around Planet Q.
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