Question

A large punch bowl holds 3.95 kg of lemonade (which is essentially water) at 20.0

Answer 1

heat lost by lemonande to reach to 0= Qavaialble = Ml*Cw*dT = 3.95*4190*20 = 331010 J

heat reqiured for ice to melt = Mice*ice*10.2 + Mice*Lf

Qreq = (1.72*2100*10.2)+(1.72*334000) = 611322.4 J

Q req > Q available

so the entire ice cannot melt

let m ice melts

Qreq = Mice*cice*10.2 + m*Lf

Qreq = (1.72*2100*10.2)+(m*334000)

Qreq = Qavailable

(1.72*2100*10.2)+(m*334000) = 331010

m = 0.881 kg

amount of ice left = 1.72-0.881 = 1.72-0.881 kg <---answer