The vector product of vectors A⃗ and B⃗ has magnitude 12.0 m2 and is in the +z-direction.Vector A⃗ has magnitude 4.0 m and is in the −x-direction. Vector B⃗ has no x-component.
Part A: What is the magnitude of vector B⃗ ? (I solved this question the answer is 3 and it's correct)
Part B: What is the direction angle θ of vector B⃗ measured from the +y-direction to the +z-direction? (This is the part that I didn't get it correct)
PART 3:
Given that the vector product of A and B is along positive z-axis.
Hence, the vectors A and B are lying on the x-y plane.
Also, we have, vector A is directed along -x direction and vector B has no x-component, means that vector B is perpendicular to x-axis also.
Hence, We can say that B is directed along positive +y-axis (using right hand thumb rule).
Hence the angle θ is given by:
(Note : If this answer shows wrong, another option is θ = 270^{o}. This is also possible)
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