A 1.10 kg hollow steel ball is submerged in water. Its weight in water is 8.75 N. The volume of the cavity inside the ball is (density of steel is 7,900 kg/m^{3})
Multiple Choice
1.39 × 10^{−4} m^{3}.
1.13 × 10^{−4} m^{3}.
6.79 × 10^{−5} m^{3}.
2.07 × 10^{−4} m^{3}.
1.59 × 10^{−5} m^{3}.
Let the volume of the cavity inside the ball is V.
Let the mass of the water displaced by the ball is m.
The mass of the water displaced by the ball is
From the Archimedes principle the volume of displaced water equals the volume of the cavity of the ball.
The volume of the cavity of the ball is
The volume of the cavity of the ball is 2.0710-4 m3.
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