Question

1- A force acting on a machine part is F = -4.5 i + 3.9 j...

1- A force acting on a machine part is F = -4.5 i + 3.9 j . The vector from the origin to the point where the force is applied is r = -0.59 i + 0.23 j. Calculate the magnitude of the vector torque, in N-m. Let a quantity along the positive axis be positive.

2-  The flywheel of an engine has moment of inertia 2.1 kg m2 about its rotation axis. What constant torque is required to bring it up to an angular speed of 406 rev/min in 6.96 s, starting from rest, in N-m?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Force F= (2.84 i - 1.39 k)N acts on a pebble with position vector r= (6.54...
Force F= (2.84 i - 1.39 k)N acts on a pebble with position vector r= (6.54 j - 1.60 k)m , relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (4.96 m, 0, -1.43 m)?
1)A 1kg solid ball (I=2/3mr^2) rolls on a horizontal surface at the rate of 20m/s. its...
1)A 1kg solid ball (I=2/3mr^2) rolls on a horizontal surface at the rate of 20m/s. its total kinetic energy is 2)the angular momentum of a particle of mass 0.01kg and position vector r=(10i+6j)m and moving with a velocity 5i m/s about the origin is 3)a flywheel is given a speed of 900rpm in 15s. determine the linear acceleration of a point 0.5m from the horizontal axis is 4)a wheel of radius 0.04 and moment of inertia 3.2x10^-4kgm^2 has a constant...
An object moving in the xy-plane is subjected to the force F = 2xy i +...
An object moving in the xy-plane is subjected to the force F = 2xy i + 3y j N, where x and y are in m. a. The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis. How much work does the force do? b. The particle moves from the origin to the point with coordinates (a, b) by moving first along the...
1) The combination of an applied force and a friction force produces a constant total torque...
1) The combination of an applied force and a friction force produces a constant total torque of 35.8 N · m on a wheel rotating about a fixed axis. The applied force acts for 5.90 s. During this time, the angular speed of the wheel increases from 0 to 10.1 rad/s. The applied force is then removed, and the wheel comes to rest in 60.1 s. (a) Find the moment of inertia of the wheel.   kg · m2 (b) Find...
A) A man holds a 185-N ball in his hand, with the forearm horizontal (see the...
A) A man holds a 185-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force , which is applied perpendicular to the forearm. The forearm weighs 18.2 N and has a center of gravity as indicated. Find (a) the magnitude of and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone...
1) A torque of 1.20 N m is applied to a thin rod of mass 2.50...
1) A torque of 1.20 N m is applied to a thin rod of mass 2.50 kg and length 50.0 cm pivoted about its center and at rest. How fast is the rod spinning after 4.25 s? a. 32.6 rad/s b. 8.16 rad/s c. 97.9 rad/s d. 24.5 rad/s 2) A torque of 1.20 N m is applied to a thin rod of mass 2.50 kg and length 50.0 cm pivoted about one end and at rest. How fast is...
A child pushes her friend (m = 25 kg) located at a radius r = 1.5...
A child pushes her friend (m = 25 kg) located at a radius r = 1.5 m on a merry-go-round (rmgr = 2.0 m, Imgr = 1000 kg*m2) with a constant force F = 90 N applied tangentially to the edge of the merry-go-round (i.e., the force is perpendicular to the radius). The merry-go-round resists spinning with a frictional force of f = 10 N acting at a radius of 1 m and a frictional torque τ = 15 N*m...
1)A 1.0 kg mass is located at (2.3, 0, -7.9) m and moving at (0, 5.7,...
1)A 1.0 kg mass is located at (2.3, 0, -7.9) m and moving at (0, 5.7, 3.9) m/s. What is the angular momentum of this mass about the origin? A. (-3.0, 0.0, -76) B. (13, -9.0, 45) C. (45, -9.0, 44) D. (45, -9.0, 13) E. (-76, 0.0, -3.0) F. (0.0, 0.0, 0.0) G. (-13, 9.0, -45) H. (-45, 9.0, -13) I. (76, 0.0, 3.0) J. (-45, 9.0, -44) K. (-44, 9.0, -45) L. (44, -9.0, 45) M. (3.0, 0.0,...
1. Review your notes from 02-28 and your calculation of the moment of inertia of the...
1. Review your notes from 02-28 and your calculation of the moment of inertia of the "rigid rotator," two masses, 7 kg each attached to a light titanium bar (neglect this weight) separation 4.20 m rotation axis halfway between the two masses, perpendicular to the bar. Our calculation of moment of inertia Iwas I = ∑ left, right ( m r 2 ) = ( 7 k g ) ( 2.10 m ) 2 + ( 7 k g )...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT