-How does the work change as you increase the applied force? Find the acceleration of the cart from your measurements. Is there a pattern concerning the work done by the force and the acceleration of the cart? For each run the cart started from rest. You can calculate from the equations of motion the final speed of the cart. It is given by the expression - final speed =square root ( 2 x acceleration x distance)
Mass (kg) |
Force (N) |
Acc (m/s/s) |
distance (m) |
Final Speed (m/s) |
Work (J) |
1.500 |
0.098 |
0.065 |
2.00 |
||
1.500 |
0.196 |
0.130 |
2.00 |
||
1.500 |
0.294 |
0.196 |
2.00 |
||
1.500 |
0.392 |
0.260 |
2.00 |
||
1.500 |
0.490 |
0.326 |
2.00 |
||
2.000 |
0.098 |
0.047 |
2.00 |
||
2.000 |
0.196 |
0.098 |
2.00 |
||
2.000 |
0.392 |
0.196 |
2.00 |
||
2.000 |
0.490 |
0.245 |
2.00 |
||
2.000 |
0.588 |
0.294 |
2.00 |
||
Trial 3 |
|||||
3.000 |
0.098 |
0.032 |
2.00 |
||
3.000 |
0.196 |
0.065 |
2.00 |
||
3.000 |
0.392 |
0.131 |
2.00 |
||
3.000 |
0.490 |
0.163 |
2.00 |
||
3.000 |
0.588 |
0.196 |
2.00 |
||
Trial 4 |
|||||
4.000 |
0.098 |
0.023 |
2.00 |
||
4.000 |
0.196 |
0.049 |
2.00 |
||
4.000 |
0.392 |
0.088 |
2.00 |
||
4.000 |
0.490 |
0.123 |
2.00 |
||
4.000 |
0.588 |
0.147 |
2.00 |
formula use v = sqrt( 2 * A * d)
w = f * d
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