Question

An object with a height of 40cm is placed 2.4m in front of a concave mirror with a focal length of 0.52m.

Part A

Find the location of the image produced by the mirror using the mirror and magnification equations.

Express your answer using two significant figures.

Part B

Find the magnification of the image produced by the mirror using the mirror and magnification equations.

Express your answer using two significant figures.

Answer 1

object distance s = 2.4 m

focal length f = 0.52 m

image distance s' = ?

part A)

using mirror equation

1/s + 1/s' = 1/f

1/2.4 + 1/s' = 1/0.52

1/s' = 1/0.52 - 1/2.4

1/s' = (2.4-0.52)/(0.52*2.4)

s' = (0.52*2.4)/(2.4-0.52)

s' = +0.66 m <--------answer

part B)

magnification m = -s'/s

m = -0.66/2.4 = -0.28

lml = 0.28 <-----answer

s' = positive , the image is real

m = negative so the image is inverted

lml <1 the image size is smaller than object

the final image is real inverted and smaller than the object