Question

A single conservative force acts on a 5.00 kg particle. The equation Fx = (2x + 4) N describes this force, where x is in meters. As the particle moves along the x axis from x = 3.00 m to x = 7.00 m, calculate the following. (a) the work done by this force on the particle J (b) the change in the potential energy of the system J (c) the kinetic energy the particle has at x = 7.00 m if its speed is 3.00 m/s at x = 3.00 m

Answer #1

A conservative force F(x) acts on a 2.0 kg particle
that moves along an x axis. The potential energy U(x) associated
with F(x) is graphed in the figure. When the particle is at x = 2.0
m, its velocity is -1.265 m/s.
What is F(2.)? (sign gives direction)
Between what positions on the left and right does the particle
move? Left side?
Right side?
What is the particle's speed at x = 7.0 m

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b) Find the potential energy due to this force, at position
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c) Using either...

Calculate the work done by the conservative force F = (2x^3 +
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A single force acts on a 3.7 kg particle-like object in such a
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In order to get full credit, you need to show all your
work.
A force Fx = cx3 (c =
3.0 N/m3) acts on an object with mass 40 kg that is
sliding along a rough horizontal floor (x-axis) with
coefficient of kinetic friction of 0.2.
What is the work done by the force Fx on
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x2 = 6.0 m?
What is the work done by the force of...

A particle with a mass m = 2.00 kg is moving along the
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function U(x) = (2.00
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released from rest at the position x = 6.40 m, determine
the following. (The sign is important. Be sure not to round
intermediate calculations.)
(a) total mechanical energy of the particle at any position:
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(b) potential energy of the particle at the position x...

A 1.0 kg ball is moving in a conservative force-field that is
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What is the ball's speed at the position you found...

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A single, nonconstant force acts in the +x-+x-direction on a
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where A=4.43 m, B=3.12 m/s, and C=0.308 m/s.
How much work is done by this force from t=0 st=0 s to t=2.14
s?

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