A bicyclist starting at rest produces a constant angular acceleration of 1.10 rad/s2 for wheels that are 37.5 cm in radius.
HINT
(a)
What is the bicycle's linear acceleration (in m/s2)? (Enter the magnitude.)
m/s2
(b)
What is the angular speed of the wheels (in rad/s) when the bicyclist reaches 10.6 m/s?
rad/s
(c)
How many radians have the wheels turned through in that time?
rad
(d)
How far (in m) has the bicycle traveled?
m
a) Linear acceleration
where r is the radius =37.5 cm=0.375m
linear acceleration= 1.10*0.375 m/s2=0.41m/s2
b) Linear velocity (v)=10.6 m/s ; using the formula
now angular velocity=v/r=10.6/0.375=28.26 sec-1
c) now let time taken to reach v=10.6 m/s is t sec ,initial velocity u=0 m/s
using v=u+at ; t=v/a=10.6/0.41 s=25.85 sec
using
and
=28.26*25.85=730.5 deg=12.74 radians
d) Distance travelled(s)= 1/2 *a*t2 as u=0
so s=0.5*0.41*(25.85)2 =136.9 m
Get Answers For Free
Most questions answered within 1 hours.