Question

Mars has two moons, Phobos and Deimos. Phobos orbits at 6000 km above the surface of Mars, closer than any other moon in the solar system, once every 7.66 hours. (Radius of Mars = 3389 km). You want to put an artificial satellite (the Mars Reconnaissance Orbiter in this case) into a circular orbit at a height of 300 km above the surface of Mars. This process, called orbital insertion, requires the orbiter to speed up or slow down to the correct speed. Based on what you know about Phobos, what speed will the orbiter need for this orbit? (Give your answer in meters per second).

Answer #1

The centripetal force (provided by gravitational force) of a satellite in circular speed is given by

Now, for Phobos

The period of Phobos is

So, the speed of Phobos is

That gives us

Now for our satellite

**So, the speed of the satellite must be 3412.9
m/s.**

Two satellites are in circular orbits around the earth. The
orbit for satellite A is at a height of 406 km above the earth's
surface, while that for satellite B is at a height of 904 km. Find
the orbital speed for satellite A and satellite B.

Two satellites are in circular orbits around the earth. The
orbit for satellite A is at a height of 556 km above the earth’s
surface, while that for satellite B is at a height of 888 km. Find
the orbital speed for (a) satellite A and
(b) satellite B.

The orbital period of a satellite is 1 hr 34 min. It orbits at
an altitude of 480 km above the Earth's surface.
a) Determine the initial velocity in order to launch the
satellite in that circular orbit.
b) Find the speed of the satellite once its circular orbit has
been achieved. Assume a uniform circular motion.

a) For a satellite to be in a circular orbit 850 km above the
surface of the earth, what orbital speed must it be given?
b) What is the period of the orbit (in hours)?

A satellite of mass 1000 kg orbits the Planet X at a distance of
6000 km above its surface. The satellite circles Planet X
once every 7 hours. Determine the following quantities:
The orbital velocity of the satellite in m/s about planet
X;
The acceleration of the satellite;
The Force that Planet X applies on the satellite; and
the Mass of Planet X.

Question: A satellite of 1000 kg orbits the planet X at a
distance of 6000 km above its surface. The satellite circles planet
X once every 7 hours. Determine the following:
a.The orbital velocity of the satellite in m/s about planet
X;
b. The acceleration of the satellite;
c. the force that planet X applies on satellite
d. Mass of planet X

Satellite to be in a circular orbit 590 km above the surface of
the earth.
a?) What orbital speed must it be given?
b) What is the period of the orbit (in hours)?
Express your answer in hours

A satellite is in circular orbit at an altitude of 1800 km above
the surface of a nonrotating planet with an orbital speed of 3.7
km/s. The minimum speed needed to escape from the surface of the
planet is 8.4 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
59 min.
83 min.
75 min.
67 min.
51 min.

A satellite is in circular orbit at an altitude of 1500 km above
the surface of a nonrotating planet with an orbital speed of 3.4
km/s. The minimum speed needed to escape from the surface of the
planet is 8 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
A)59 min.
B)45 min.
C)72 min.
D)65 min.
E)52 min.

A 3450-kg spacecraft is in a circular orbit 1630 km above the
surface of Mars. How much work must the spacecraft engines perform
to move the spacecraft to a circular orbit that is 3560 km above
the surface?

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