An electron is located on the ?x‑axis at ?0=−8.77×10−6 mx0=−8.77×10−6 m. Find the magnitude and direction of the electric field at ?=8.97×10−6 mx=8.97×10−6 m on the ?x‑axis due to this electron.
What is the direction?
negative ?x‑direction
positive ?x‑direction
neither of these
Problem is solved using the formula of electric field due to a point charge and basics of coordinate system.
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