Question

1. Two particles, both carrying charge 6 C are traveling parallel to each other with velocities of v⃗ =13000i^v→=13000i^ in m/s. They are positioned at the points (0,4,0)(0,4,0) and (0,−4,0)(0,−4,0). What is the magnitude and direction of the magnetic field at (0,4,0)(0,4,0) due to the particle located at (0,−4,0)(0,−4,0)? [Enter the magnitude in answer box 1 and the direction as one of either "in", "out", "up", "down", "left", or "right" in answer box 2. Assume that the xx-axis corresponds to left/right, the yy-axis corresponds to up/down, and the zz-axis corresponds to in/out.]

   Correct, computer gets: 1.22e-04 T, out
   
   8) What is the force exerted by the magnetic field you calculated above on the particle at that location? Compare this to the direction of the electric force on the particle. [Enter the magnitude of the force in the first answer box and its direction in the second. Enter the direction of the electric force on the particle in the third box. For the directions enter either "in", "out", "up", "down", "left", or "right"]

   Yes, Computer gets: 9.51e+00 N, down, up
   
   9) How fast would the particles have to travel in order for there to be a balance between the magnetic and electric forces they exert on each other?

Pls answer number 9

Answer 1